Backtracking
BACKTRACKING
Backtracking is an algorithmic-technique for solving problems recursively by trying to build a solution incrementally, one piece at a time, removing those solutions that fail to satisfy the constraints of the problem at any point of time (by time, here, is referred to the time elapsed till reaching any level of the search tree).
Backtracking can be defined as a general algorithmic
technique that considers searching every possible combination in order
to solve a computational problem.
There are three types of problems in backtracking –
- Decision Problem – In this, we search for a feasible solution.
- Optimization Problem – In this, we search for the best solution.
- Enumeration Problem – In this, we find all feasible solutions.
PSEUDO CODE:
1. Recursive backtracking solution.
void findSolutions(n, other params) :
if (found a solution) :
solutionsFound = solutionsFound + 1;
displaySolution();
if (solutionsFound >= solutionTarget) :
System.exit(0);
return
for (val = first to last) :
if (isValid(val, n)) :
applyValue(val, n);
findSolutions(n+1, other params);
removeValue(val, n); 2.Finding whether a solution exists or not boolean findSolutions(n, other params) :
if (found a solution) :
displaySolution();
return true;
for (val = first to last) :
if (isValid(val, n)) :
applyValue(val, n);
if (findSolutions(n+1, other params))
return true;
removeValue(val, n);
return false;
RAT IN A MAZE :
A Maze is given as N*N binary matrix of blocks where source block is the
upper left most block i.e., maze[0][0] and destination block is lower
rightmost block i.e., maze[N-1][N-1].
The rat can move only in two directions: forward and down.
In the maze matrix, 0 means the block is a dead end and 1 means the block can be used in the path from source to destination.
In the maze matrix, 0 means the block is a dead end and 1 means the block can be used in the path from source to destination.
Algorithm:
- Create a solution matrix, initially filled with 0’s.
- Create a recursive funtion, which takes initial matrix, output matrix and position of rat (i, j).
- if the position is out of the matrix or the position is not valid then return.
- Mark the position output[i][j] as 1 and check if the current position is destination or not. If destination is reached print the output matrix and return.
- Recursively call for position (i+1, j) and (i, j+1).
- Unmark position (i, j), i.e output[i][j] = 0.
public class RatMaze { // Size of the maze static int N; /* A utility function to print solution matrix sol[N][N] */ void printSolution(int sol[][]) { for (int i = 0; i < N; i++) { for (int j = 0; j < N; j++) System.out.print( " " + sol[i][j] + " "); System.out.println(); } } /* A utility function to check if x, y is valid index for N*N maze */ boolean isSafe( int maze[][], int x, int y) { // if (x, y outside maze) return false return (x >= 0 && x < N && y >= 0 && y < N && maze[x][y] == 1); } /* This function solves the Maze problem using
Backtracking. It mainly uses solveMazeUtil() to solve the problem. It returns false if no path is possible, otherwise return true and prints the path in the form of 1s. Please note that there may be more than one solutions, this function prints one of the feasible solutions.*/ boolean solveMaze(int maze[][]) { int sol[][] = new int[N][N]; if (solveMazeUtil(maze, 0, 0, sol) == false) { System.out.print("Solution doesn't exist"); return false; } printSolution(sol); return true; } /* A recursive utility function to solve Maze problem */ boolean solveMazeUtil(int maze[][], int x, int y, int sol[][]) { // if (x, y is goal) return true if (x == N - 1 && y == N - 1 && maze[x][y] == 1) { sol[x][y] = 1; return true; } // Check if maze[x][y] is valid if (isSafe(maze, x, y) == true) {
// mark x, y as part of solution path sol[x][y] = 1; /* Move forward in x direction */ if (solveMazeUtil(maze, x + 1, y, sol)) return true; /* If moving in x direction doesn't give solution then Move down in y direction */ if (solveMazeUtil(maze, x, y + 1, sol)) return true; /* If none of the above movements works then BACKTRACK: unmark x, y as part of solution path */ sol[x][y] = 0; return false; } return false; } public static void main(String args[]) { RatMaze rat = new RatMaze();
int maze[][] = { { 1, 0, 0, 0 }, { 1, 1, 0, 1 }, { 0, 1, 0, 0 }, { 1, 1, 1, 1 } }; N = maze.length; rat.solveMaze(maze); } }
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